Help the world stop coronavirus! Stay home!

Prev Next

Java / XML

How do I validate an XML file against XSD file?

The Java runtime library supports validation which is backed by Apache Xerces parser.

import java.io.File;
import java.io.IOException;
import java.net.MalformedURLException;
import java.net.URL;

import javax.xml.XMLConstants;
import javax.xml.transform.Source;
import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.Schema;
import javax.xml.validation.SchemaFactory;
import javax.xml.validation.Validator;

import org.xml.sax.SAXException;

public class XMLValidation {

	public static void main(String[] args) throws MalformedURLException {
		URL schemaFile = new URL("http://host:port/filename.xsd");
		Source xmlFile = new StreamSource(new File("web.xml"));
		SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
		try {
			Schema schema = schemaFactory.newSchema(schemaFile);
			Validator validator = schema.newValidator();
			validator.validate(xmlFile);
			System.out.println(xmlFile.getSystemId() + " is valid.");
		} catch (SAXException e) {
			System.out.println(xmlFile.getSystemId() + " is NOT valid xml, The reason is:" + e);
		} catch (IOException e) {
		}
	}

}

❤Cash Back At Stores you Love !!!❤

Earn your $10 reward when you make your first purchase through Ebates by signing up with clicking below button.

Ebates Coupons and Cash Back

More Related questions...

Show more question and Answers...

Garbage collection

Comments & Discussions